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822 Posts

V = I * R

where V = voltage (volts)

where I = current (amperes)

where R = resistance (ohms)

Just go here and read:

http://www.casemodgod.com/leds_and_modding.htm

After you're done, and if you still don't understand, just give me the recommended voltages of each of the LEDs and each of their resistances and I'll do the rest of the math and I'll tell you what to do. All of this stuff is explained in entry level physics books.

Here's a circuit I'm building for a fakey car alarm LED flasher... only it's night rider style... 20 LEDs, and they're going to go around the perimeter of the center console of the 3000GT. It's going to look really neat.

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8,421 Posts

^ Negative ^LED ^Resister ^+12V

Note flat spot is Neg-

Resister is usally around 1k

Well, either one will work well by itself, if they are both the same LEDs. But you didn't say you had two. You only mentioned one.bluescort said:I am hooking up two with one resistor and I also would like to know witch led will work as a single unit with a resistor

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874 Posts

If you hook the lights up in series, just add the voltages up, and the mA is the mean mA. If you hook them in parallel, then the voltage is the mean voltage of the LEDs.

Ex. If you hook up 3 LEDs (identical @ 3V and 20 mA) in Parallel, then the voltage needed is 3V and the amphere's (sp?) needed is 60 mA.

If you hook up the same 3 LEDs in series, then the voltage need is 9V, and the ampherage (sp?) needed is 20 mA.

bluescort, this should solve your problem.[/url]

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